If you visited Mount Shasta City (elevation 900 m [3,000 ft]) and found the outside air temperature to be 27C (81F), what would the air temperature at the summit of Mount Shasta (elevation 4200 m [14,000 ft]) at that moment -- assuming that the temperature conditions with altitude change at an average, or normal lapse rate?

5.9C, (42.6)F

Explanation:

The temperature at height above ground level is given as

temperature at height above ground level = Ground Temperature - (height difference *average laps rate)

where average laps rate =6.39c/km

The following data are given data were given

Shasta city elevation=900m=0.9km

summit elevation =4200m=4.2km

Hence the height differences is 4.2km-0.9km

Hence the height differences=3.3km

Using the formula

temperature at height above ground level = Ground Temperature - (height difference *average laps rate)

we arrive at

temperature at height above ground level =27-(3.3*6.39)

temperature at height above ground level =5.913 C

converting to Fahrenheit

(5.913*9/5)+32=42.6F

and 1and 1

it is given that trillions of microbes make up to 1% to 3% of the body mass.

let's take average of this percentage: 2%

consider the average mass of the human body as 70 kg.

then, trillions of microbes would have mass  

therefore, 100 trillion micro-organisms would weigh:

this is an approximate value and could change depending on the mass of the human body and percentage of the microbes present in it.

average mass per microorganism =