A bullet of mass m traveling horizontally at a very high speed v embeds itself in a block of mass M that is sitting at rest on a nearly frictionless surface. What is the final speed vf of the block-bullet system after the bullet embeds itself in the block?

Explanation:

Given that

mass of the bullet = m

Speed of the bullet = v

mass of the block = M

Initial speed of the block = 0

The final speed of the bullet and block combine = vf

As we know that ,if external force on the system is zero then the linear momentum of the system will remain conserve.

Pi= Pf

So by using linear momentum conservation

m v + M x 0 = (M+m) vf

m v = (M+m) vf

Therefore the final spped of the system will be

d₁ = displacement of tern from arctic to antarctic = 11000 miles

d₂ = displacement of tern from antarctic to arctic =   - 11000 miles

d = total displacement for the journey

total displacement for the journey is given as

d = d₁ + d₂

d = 11000 + (-11000)

d = 0 miles

t₁ = time of travel from arctic to antarctic = 3 months = 3 x 30 days = 90 days

t₂ = time of travel from antarctic to arctic = 3 months = 3 x 30 days = 90 days

t = total time of travel

total time of travel is given as

t = t₁ + t₂

t = 90 + 90

t = 180 days

average velocity is given as

average velocity = total displacement/ total time

v = d/t

v = 0/180

v = 0 miles/day

connect the batteries in series and hope