A motorcycle has a velocity of 24 m/s, due south as it passes a car with a velocity of 15 m/s, due north. What is the magnitude and direction of the velocity of the motorcycle as seen by the driver of the car?

39m/s due south.

Let's take the direction due south to be negative(-ve) and

Let's take the direction due north to be positive (+ve)

Also,

Let the velocity of the motorcycle be

Let the velocity of the car be

Let the velocity of the motorcycle as seen by the car be

Using the principle of relativity;

= -       -------------------------(i)

From the question;

= 24m/s due south = -24m/s    [since the south direction is -ve]

= 15m/s due north = +15m/s    [since the north direction is +ve]

Substitute these values into equation (i) as follows;

= -24 - (+15)

= -24 - 15

= - 39 m/s

Since the result of is negative, that means its direction is due south.

Therefore, the velocity of the motorcycle as seen by the car is 39m/s due south.

the components of a vector are the parts of the vectors that are to each other.

b perpendicular

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