A power supply maintains a potential difference of 82.1 V 82.1 V across a 1010 Ω 1010 Ω resistor. What is the current in the resistor?

0.081A

According to Ohm's law, the potential difference (V) across a resistor of resistance R, is given by;

V= I x R             (i)

Where;

I = the current flowing through the resistor

From the question;

V = 82.1V

R = 1010Ω

Substitute these values into equation (i) as follows;

82.1 = I x 1010

Solve for I;

I = 82.1 / 1010

I = 0.081A

Therefore, the current in the resistor is 0.081A

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