8. Two forces of 10 N and 30 N are applied to a 10 kg box. Find (1) the box’s acceleration when both forces point due east and (2) the box’s acceleration when 10 N force points due east and 30 N force points due west.

(1) acceleration, a = 4 m/  (2) acceleration of 10 N, = 1 m/ and acceleration of 30 N, = 3 m/

Explanation:

Here, the acceleration of the object could be found using the equation derived in the second law of motion. The equation is given as, F = ma where m is the acceleration of the object, m is the mass of the object and F is the applied on the object. Let be the acceleration for force 10 N, to find acceleration rearrange the equation to a = . When we substitute 10 N force and 10 kg mass of the box in the equation. We will get = 1 m/ Let  be the acceleration for force 30 N, to find acceleration rearrange the equation to F = . When we substitute 30 N force and 10 kg mass of the box in the equation. We will get = 3 m/ To find the combined, just add the force and substitute in the above equation. Hence, a = 4 m/

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