A 4 kg ball moves with a velocity of 10m/s wide with a 16kg ball moving with a velocity of 4m/s (a) calculate the velocity of ball in each case they stick together on impact and loss of energy resulting from impact (b) state the principle used to calculate the velocity of the ball.

5.2m/s

Explanation:

Mass, m1 = 4kg

m2= 16kg

Velocity before collision for mass 1, u1 = 10m/s

Velocity before collision for mass 2, u2 = 4m/s.

Velocity after collision, V = ?

From law of conservation of linear momentum

Sum of momentum before collision = sum of momentum after collision.

Remember momentum = mass x velocity

Therefore,

m1u1 +m2u2 = (m1 + m2)V

4x10 + 16x4 = (4+16)V

40+64 = 20V

20V= 104/20

Divide both sides by 20

V = 104/20

V = 5.2m/s

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answer: the correct answer is 1.

explanation: there are various process in which a radioactive nuclei decays:

1) alpha decay: in this process, a heavier nuclei decays into lighter nuclei by releasing alpha particle. the mass number is reduced by 4 units.

2) electron capture: in this decay process, a parent nuclei absorbs an electron and gets converted into a neutron. simply, a proton and an electron combines together to form a neutron. mass number does not change in this process.

3) gamma ray emission: it is a decay process in which an unstable nuclei gives excess energy by a spontaneous electromagnetic process. this decay releases . this process does not change the mass number.

4) positron emission: it is a type of decay process, in which a proton gets converted to neutron and an electron neutrino. this is also known as -decay. in this the mass number remains same.

from the above information, we see that only alpha-decay is producing a change in the mass number of the nucleus.

truck y has a greater velocity than truck x.