Two blocks, A and B, are connected by a rope. A second rope is connected to block B and a steady, horizontal tension force of T is applied. The system moves at a constant speed across the ground. Block B experiences a friction force of f. T = 50N f = 10N
What is friction force acting on block A?

40 N

Explanation:

We are given that

Speed of system is constant

Therefore, acceleration=a=0

Tension applied on block B=T=50 N

Friction force=f=10 N

We have to find the friction force acting on block A.

Let T' be the tension in string connecting block A and block B and friction force on block A be f'.

For Block B

Where =Mass of block B

Substitute the values

For block A

Where Mass of block A

Substitute the values

Hence, the friction force acting on block A=40 N

trig 15.3 cos

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