A skydiver jumps out of a plane waering a suit and decleration due to air i s 0.45 m/s^2 for each 1 m/s, skydyvers initial value problems that models the skydiver velocity is v(t). temrinal speed assuming that accelration due to gravity is 9.8m/s

Explanation:

Given,

Air resistance, = 0.45 m/s² for each 1 m/s

Air resistance for velocity v = 0.45 v.

Terminal velocity = ?

acceleration due to gravity= g = 9.8 m/s²

 now,

a = 0.45 v

we know,

integrating both side

When a body is moving at terminal velocity, Force due to gravity is equal to  force due to air resistance.

 m a = m g

    0.45 v = 9.8

Hence, the terminal velocity of the skydiver is equal to 21.77 m/s.

answer: the correct answer is   air pressure at the top of mount everest is higher than at the bottom of the grand canyon.

hope this : )

explanation:

one person pulls 90n one way and the other has 100n pulling the other way.

so the net force = 90 - 100 = -10n,

or the ans can be 10n if the picture shows -90n and 100n instead.