A cannonball is fired horizontally from the top of a cliff. The cannon is at height H = 70.0 m above ground level, and the ball is fired with initial horizontal speed v0. Assume acceleration due to gravity to be g = 9.80 m/s2. Given that the projectile lands at a distance D = 150 m from the cliff, find the initial speed of the projectile, v0. Express the initial speed numerically in meters per second.

39.7 m/s

Explanation:

The motion of the cannonball consists of a horizontal and a vertical motion. The vertical motion is under gravity while the horizontal motion is a constant-velocity motion. Both motions span the same time interval. We consider them differently.

Vertical motion:

Acceleration,

Initial velocity, (since the ball was fired horizontally)

Distance,

Using the equation ,

Horizontal motion:

Since there is no acceleration, horizontal velocity = horizontal distance ÷ time for vertical motion.

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