A race car rounds one end of a speedway. This end of the track is a turn with a radius r of approximately 187 ft. If the track is assumed to be completely flat and the race car is traveling at a constant 65.00 mi/h around the turn, what is the race car's centripetal (radial) acceleration a c ?

the centripetal acceleration of the race car is found to be 48.6 ft/s².

Explanation:

The centripetal acceleration of a body performing a circular motion is given by the following formula:

Centripetal Acceleration = ac = v²/r

where,

r = radius of the circular path (track) = 187 ft

v = speed of the body (car) = 65 mi/h

converting it to ft/s:

v = (65 mi/h)(5280 ft/1 mi)(1 h/3600 sec)

v = 95.33 ft/s

therefore,

ac = (95.33 ft/s)²/187 ft

ac = 48.6 ft/s²

Thus, the centripetal acceleration of the race car is found to be 48.6 ft/s².

a cold ice-tea.

pour in room temperature or cold water. cover the pitcher and refrigerate. steep white or green tea for 6 to 8 hours; steep black or oolong tea for 8 to 12 hours.jun 28, 2015