Car B has the same mass as Car A but is going twice as fast. If the same constant force brings both cars to a stop, how far will car B travel in coming to rest as compared to the distance car A traveled

By using the third equation of motion,

By substituting the values,

→

→

and,

→

hence,

→

Thus the above response is appropriate.

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four times

Explanation:

Given

mass of both cars A and B are same suppose m

but velocity of car B is same as of car A

Suppose velocity of car A is u

Velocity of car B is 2 u

A constant force is applied on both the cars such that they come to rest by travelling certain distance

using  to find the distance traveled

where, v=final velocity

u=initial velocity

a=acceleration(offered by force)

s=displacement

final velocity is zero

For car A

For car B

divide 1 and 2 we get

thus

distance traveled by car B is four time of car A