An electric field does 2.75 ✕ 103 eV of work on a carbon nucleus of charge 9.61 ✕ 10−19 C. Find the change in the nucleus' electric potential and electric potential energy in joules.

To solve this problem we will apply the concepts related to the calculation of work through the equations of the electric variables that define the energy stored on a body, such as the product of the load and the voltage. Later we will find the change in potential energy, such as the product between the electric field and the charge of the electron.

Here,

q = Charge of nucleus

Electric Potential

But at the same time, we have that Work is equal to the electric field for the charge of a electron, then the work made is,

Where,

Then replacing we have that,

Then from the first equation we have,

PART B)

Change in

do you have a formula possibly

the answer is the first electromagnet (a). this is because it has more coils around the ferromagnetic material. increasing the number of coils increases the surface area in which the metal interacts with the current in the coil. this enables more atoms in the metal to become aligned hence becoming more magnetized.