Jim pushes off an asteroid in deep space where he was exiled for crimes committed. The
force of Jim's push is 300 N. Jim has a mass of 100 kg and the asteroid has a mass of 1000
kg. What is the acceleration of the asteroid?
O
A.
0.3 meters per second squared away from Jim.
O B. 3.0 meters per second squared towards Jim.
O
c. 300,000 meters per second squared away from
Jim.
OD 30,000 meters per second squared.

the velocity you are looking for is made up of two parts: horizontally velocity, vh, and its vertical velocity, vv. the actual velocity of the ball will be these two parts added together, and because velocity is a vector then they will need to be added vectorially.  

neglecting air resistance etc etc.,  

the horizontal velocity component will be constant (because there is no accelerating force in the horizontal direction.  

vh = 8 ms-1  

the vertical velocity component has an accelerating force: 'g'.  

using v = u +at where a = g = 9.81 ms-2.  

the vertical component of velocity, vv = 0 + gt = vv =9.81 x 2  

vv = 19.62 ms-1 . the zero appears because the virtical component of velocity at time t=0 is zero. remember, the ball was thrown horizontally.  

how fast it will be moving (it actual path (being a parabola )) will be the vector sum of these two.  

adding vectorally gives: -  

v = sqr root (8^2 + 19.62^2) = sqr root(64+384.9) = 21.18 or 21.2 ms-1

spectral lines lyman is one set