A finch rides on the back of a Galapagos tortoise, which walks at the stately pace of 0.060 m/s. After 1.1 minutes the finch tires of the tortoise's slow pace, and takes flight in the same direction for another 1.5 minutes at 12 m/s.

1)What was the average speed of the finch for this 2.6-minute interval? Express your answer using two significant figures.

Average speed will be equal to 6.93 m/sec

Explanation:

We have given speed of tortoise

Time t = 1.1 minute

As 1 minute = 60 sec

So 1.1 minute = 1.1×60 = 66 sec

So distance traveled by tortoise = speed ×time = 0.06×66 = 2.16 m

Now speed of finch

Time t = 1.5 minute

As 1 minute = 1.5×60 = 90 sec

So distance traveled by finch = 12×90 = 1080 m

So total distance traveled = 1080+2.16 = 1082.16 m

Total time = 2.6 minute = 156 sec

So average speed

when two balls of the different masses are dropped from equal height, they reach the ground at the same time .this is because they experience the same acceleration.

the acceleration is independent of mass.

thus when they are dropped they will always maintain the same velocity and travel the same distance (neglect air resistance of course) at the same time.