A burglar attempts to drag a 105 kg metal safe across a polished wood oor Assume that the coecient of static friction is 0.4, the coecient of kinetic friction is 0.3, and that the burglar can apply a pushing force of 520 N on the metal safe. What is the acceleration of the metal safe across oor?

a = 2.012 m/s²

Explanation:

given,

Mass of the metal safe, M = 105 Kg

Pushing Force,F= 520 N

coefficient of kinetic friction, μ_k = 0.3

acceleration of the safe on the floor = ?

frictional force acting on the safe

now, Net Force acting on the safe

we know,

F = m a

a = 2.012 m/s²

Hence, the acceleration of the safe is equal to a = 2.012 m/s²

v=ir = 3x15 =45 v