A uniform electric field exists in a region between two oppositely-charged plates. An electron is released from rest at the surface of the negatively-charged plate and strikes the surface of the opposite plate, d = 2 cm away, 20 ns later. a) What is the speed of the electron as it strikes the second plate? b) What is the magnitude of the electric field? c) If instead, a proton is released from rest at the positively charged plate, how long would it take to get to the opposite plate?

2000000 m/s

569.375 N/C

Explanation:

m = Mass of electron =

t = Time taken = 20 ns

u = Initial velocity

v = Final velocity

s = Displacement = 2 cm

a = Acceleration

The speed of the electron is 2000000 m/s

Electric field is given by

The electric field is 569.375 N/C

m = Mass of proton =

The time taken is

waves moving from a fast medium to a slow medium will experience a reflection as light travels more slowly than red light. total internal reflection occurs when the critical angle is.

the answer is b i think