A potential difference Δ V exists between the inner and outer surfaces of the membrane of a cell. The inner surface is negative relative to the outer surface. If 1.00 × 10 − 20 J of work is required to eject a positive potassium ion (K + ) from the interior of the cell, what is the magnitude of the potential difference (in millivolts) between the inner and outer surfaces of the cell?

The magnitude of the potential difference between the inner and outer surfaces of the cell is 0.0625 V

Explanation:

Given that,

Work done

We need to calculate the magnitude of the potential difference between the inner and outer surfaces of the cell

Using formula of wok done

Where,

V = volt

W = work done

q = charge

Put the value into the formula

Hence, The magnitude of the potential difference between the inner and outer surfaces of the cell is 0.0625 V

the moon affects the earth gravitation ally, causing certain motions of that body and also producing tides in its ocean and atmosphere. the tidal wave in our atmosphere is, however, far too minute to be an effective cause in any known meteorological phenomenon.

explanation: