A potential difference Δ V ΔV exists between the inner and outer surfaces of the membrane of a cell. The inner surface is negative relative to the outer surface. If 2.20 × 10 − 20 J 2.20×10−20 J of work is required to eject a positive potassium ion (K + ) (K+) from the interior of the cell, what is the magnitude of the potential difference (in millivolts) between the inner and outer surfaces of the cell?

Explanation:

Given

Work required to eject a positive Potassium ion

Charge on the Potassium ion

During ejection Potential difference between the inner and outer membrane exert a force opposite to the direction of motion so some amount of work is required to over come this force

Work done=Potential difference\times charge

the total distance that martina travels that day is

(distance from home to mom's office) plus (distance from mom's office to school)

plus (distance from school to library) plus (distance from library to friend's house)

plus (distance from friend's house to martina's house).

(we don't know what any of these distance actually is.)