A 2.4 m long rod of mass m1 = 14 kg, is supported on a knife edge at its midpoint. A ball of clay of mass m2 = 3.5 kg is dropped from rest from a height of h = 1.4 m and makes a perfectly inelastic collision with the rod 0.9 m from the point of support. Find the angular momentum of the rod and clay system about the point of support immediately after the inelastic collision.

Explanation:

It is known that;

Now, we need to calculate the value of L, that is, angular momentum.

Therefore,

                   L= mvr

where,   m = mass

              v = velocity

              r = radius

Hence,

               L =

So,

              L =

                  = 10.37 Js

Thus, we can conclude that angular momentum of the rod and clay system about the point of support immediately after the inelastic collision is 10.37 Js.

grav potential energy

mass and volume are the answers you are looking for