Ice cubes at 0°C with a total mass of 625 g are put in a microwave oven and heated with 750. W (750. J/s) of energy for 6.00 minutes. What is the final temperature of the water from the melted ice? Assume all of the microwave energy is absorbed by the ice/water and no heat loss by the ice/water. The enthalpy of fusion for ice is 6.02 kJ/mol and the heat capacity for water is 4.18 J/g･°C.

24°C

Explanation:

m = Mass of ice = 625 g

Energy the microwave provides

Latent heat of melting = 334 J/g

Energy required to melt ice

Actual energy

= Heat capacity for water = 4.18 J/g･°C.

Energy required to melt ice will be equal to the heat absorbed

The temperature is 24°C

Explanation:

Given:

initial temperature of the ice cube,

mass of the ice cube,

power of heating by the microwave oven,

time duration of heating,

specific enthalpy of fusion of ice,

specific heat capacity of ice,

We find the energy supplied by the microwave:

The energy required by the given mass of ice to melt:

where:

M = molecular mass of the water

Remaining heat that is used in increasing the temperature of the melted ice i.e. water of 0°C:

Now the rise in temperature of water:

From the heat equation,

is the final temperature of the water after the given heat input.

that tool is called an altimeter which measures your altitude which can be used to tell which atmosphere you are currently in, including the stratosphere.

hope this ! : )

the old price per ounce is c/4.

the new price per ounce is c/3.6.

the ratio of the old price to the new one is

(c/4)/(c/3.6) = (c/c)×(3.6/4) = 0.9 . . = 9/10 . . "nine tenths" in either form