Water flows from a large drainage pipe at a rate of 1200 gal / min . What is this volume rate of flow in (a) m 3 / s , (b) liters / min , and (c) ft 3 / s

A. 0.076 m3/s.

B. 317. 01 liters/min.

C. 2.67 ft3/s.

Explanation:

A.

1 gallon = 0.0037854 m3

But 60 s = 1 min

= 1200 gallon/min * 0.0037854 m3/1 gallon * 1 min/60 s

= 0.0757 m3/s.

B.

1 gallon = 3.7854 liters

= 1200 gallon/min * 1 gallon/3.7854 liters

= 317 .01 liters/min.

C.

1 gallon = 0.13368 ft3

But 60 s = 1 min,

= 1200 gallon/min * 0.13368 ft3/1 gallon * 1 min/60 s

= 2.6736 ft3/s

come closer and become far apart and become steam/gas

force is mass*acceleration.

we have a very small mass: 11.4*0.001 kg

if we want 0.035n of force, we need an acceleration:

0.035 = 11.4*0.001*a

a = 0.035/(11.4*0.001) m/s^2