Aprojectile is fired upward at an angle θ above the horizontal with an initial speed v0. at its maximum height, what are its velocity vector, its speed, and its acceleration vector?

Explanation:

The equations of kinematics will be used to solve this question:

At its maximum height, the projectile has zero velocity in the y-direction. But its velocity in the x-direction is unaffected.

First, let's apply the above equations to the x-direction.

There is no acceleration in the x-direction. So, its velocity in the x-direction is constant during the motion.

Therefore, the velocity vector of the projectile is

The speed of the projectile is the same.

The acceleration vector is constant during the motion and equal to the gravitational acceleration, which is -9.8 downwards.

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