A0.032-kg bullet is fired vertically at 230 m/s into a 0.15-kg baseball that is initially at rest. how high does the combined bullet and baseball rise after the collision, assuming the bullet embeds itself in the ball?

Explanation:

Given data

Baseball mass m₁=0.15 kg

initial speed v₁=0

Bullet mass m₂=0.032 kg

final speed v₂=230 m/s

To find

height h=?

Solution

From conservation of momentum we know that

Now from the conservation of mechanical energy

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