What is the energy stored in the 10.5 μ f 10.5 μf capacitor of a heart defibrillator charged to 8250 v ?

356.33 J

Explanation:

Energy: This can be defined as the ability or the capacity to do work. The S.I unit of Energy is Joules (J).

The Energy stored in a capacitor = 1/2CV²

E = 1/2CV² Equation 1.

Where E = Energy stored in a capacitor, C = capacitance of the capacitor, V = potential difference across the plates of the capacitor.

Given: C = 10.5 μF  = 10.5×10⁻⁶ F, V = 8250 V.

Substitute into equation 1

E = 1/2(10.5×10⁻⁶)(8250)²

E = 357.33 J.

Thus the energy stored in the defibrillator = 356.33 J

a

explanation:

no diagram was provided, but i'm guessing it's the one i've attached to my answer.

here, a mechanical force turns the rod.   this generates an electric current in the coil, which powers the bulb.

the current is 0.6

voltage ÷ resistance = current

so 12 ÷ 20 = 0.6