Awooden block with a mass of 1000 grams is suspended by a rope from a tree. you shoot a bullet with a mass of 10 grams and a velocity of 1000 m/s. the bullet imbeds in the block causing it to swing upwards. how high in the vertical direction will the block swing?

495.05 m

Explanation:

Given:

Initial velocity of the bullet, u = 1000 m/s, mass of the bullet, m = 10 g, mass of the wooden block, M = 1000 g,

From the swinging of the wooden block just after the collision with the bullet to its maximum height, using conservation law of mechanical energy we have that,

1/2(m+M) = (m+M)gh

Where h = the vertical height of the block in the direction will the block swing, and g = acceleration due to gravity = 10

=> v=

Using the conservation law of linear momentum,

mu = (m+M)v

mu = (m+M) (where v=)

=>h = *

h=

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