To practice problem-solving strategy 16.1 sound intensity. a rescue team is searching for andrew, a geologist who was stranded while conducting research in the mountains of colorado. the team uses electronic listening devices in order to detect any shouts for . the sound waves from his shouts reaching the base camp can be approximated by a sinusoidal wave with a frequency f = 540 hz and displacement amplitude a = 4.00×10−8 m , where the sound wave properties are valid at the base camp where the measurements are being made. what sound intensity level will the rescue team measure from the frightened researcher? assume the speed of sound is v=329m/s and the density of air rho = 1.24 kg/m3 . calculate the bulk modulus b of air using the given values of the sound speed and air density. express your answer numerically in pascals.

A) I = 1.29 10⁻¹¹ W / m² , B) B = 1.34 10⁵ Pa

Explanation:

The intensity of a wave is given by

             I = P / A

Where the power of sound is

           P = ½  ρ A v w² s₀²

Angular velocity and frequency are related.

          w = 2π f

We replace

            I = ½ ρ v 4π² f² s₀²

            I = 2 π² ρ f² s₀²

Let's calculate

           I = 2π² 1.24 329 (4.00 10⁻⁸)²

           I = 1.29 10⁻¹¹ W / m²

Part B

The speed of sound is related to the properties of the medium where it propagates

        v = √ B / ρ

        B =  ρ v²

Let's calculate

        B = 1.24 329²

        B = 1.34 10⁵ Pa

d is the answer i came up with

  1.the balanced   chemical equation is as below

cu +   2 ag(no)₃ → cu(no₃)₂   +2 ag

2.the   much silver   produced   is   50.9 g

step 1: find the   moles of cu

moles =   mass÷   molar mass

  from periodic table the molar mass of cu = 63.5 g/mol

moles is therefore = 15.00 g÷ 63.5 g/mol = 0.236   moles

step 2: use the mole ratio to determine the   moles of ag

from equation above   cu: ag   is 1: 2

therefore the moles of ag   =0.236   moles   x 2/1 =0.472   moles

step 3: find the mass   of ag

mass = moles x molar mass

from periodic table   the molar mass of ag =107.87 g/mol

mass   = 0.472   moles x 107.87 g/mol = 50.9 g

3.   the   much   silver   collected worth is   1.797 oz

  convert   50.9 g   to oz

that is   1 gram = 0.0353 oz

          50.9 grams =?   oz

by cross multiplication

={(50.9 grams x 0.0353 oz) / 1   gram}   =1.797 oz