Young david who slew goliath experimented with slings beforetackling the giant. he found that he could revolve a sling oflength 0.600 m at the rate of9.00 rev/s. if he increased the lengthto 0.900 m, he could revolve the slingonly 7.00 times per second.(a) what is the speed of the stone for eachrate of rotation? 1 m/s at 9.00 rev/s2 m/s at 7.00 rev/s(b) what is the centripetal acceleration of the stone at9.00 rev/s? 3 m/s2(c) what is the centripetal acceleration at 7.00 rev/s? 4 m/s2

(a) velocity at 9 rev/s is 34.3m/s and the velocity at 7rev/s is 40.4 m/s. These were values can be gotten by using the formula v = 2(pi)R/T. Where T is the period. T = 1/w(angular velocity).

(b) acceleration at 9.0rev/s is 1961 m/s²

(c) acceleration at 7.0rev/s is 1814 m/s²

These values can be gotten by using the formula a = v²/R

Explanation:

The full solution can be found in the attachment below.

Thank you for reading.

fghbdt gjdtyg thd tghbtrg htd

step-by-step explanation:

y htf dfh drthf hdt hdthyty hty