If a proton and an electron are released when they are 5.50×10−10 mm apart (typical atomic distances), find the initial acceleration of each of them. express your answer in meters per second squared.

Explanation:

Distance between proton and electron = r = 5.5 x 10⁻¹³ m

Magnitude of charge on electron and proton = 1.67 x 10⁻¹⁹ C

To find their initial acceleration first force between them is:

Initial acceleration of electron and proton are found using

F=ma

a=F/m

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