Acharge q is located inside a rectangular box. theelectric flux through each of the six surfaces of the box is: electric flux 1 = +1500 n*m^2/c, electric flux 2 = +2200n*m^2/c, electric flux 3 = +4600 n*m^2/c, electric flux 4 = -1800n*m^2/c, electric flux 5 = -3500 n*m^2/c, and electric flux 6 =-5400 n*m^2/c. what is q?

To solve this problem we will apply the laws of gaus that relate the Electric Flow as the charge of the object on the permittivity constant of free space. Mathematically this is

Rearranging to find the charge,

Here

Q = Charge

Electric Flux

Permittivity of free space

The total flux would be

Replacing we have that,

Therefore the charge Q inside a rectangular box is -21.24nC

when a device is used in a circuit in which the voltage is 81 v, the current flowing through the device is 3 a. what is the resistance of the device?

a. 27 ω

b. 40.5 a

c. 243 ω

d. 243 a

the correct answer is a. 27