Astudent creates a circuit that consists of a single battery and four resistors that are arranged as shown. how much energy is dissipated by the 2 ω resistor after 120 s if the total current drawn from the battery is 5 a?

6000JOules

Explanation:

My friend this is quite easy.

There is an equation.

The energy is also presumed as heat.

To calculate the heat in a circuit or the energy the equation is H=I(square) RT

Heat= square of current x resistance x time

Here I=5a.

R=2 ohm

T=120s

H= 5x5x2x120=6000J

I hope this satisfies you.

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the box does not move because you need to use a force greater than 300 n. you are only using 50 n. it needs to at least be 301 n for the box to move because then it is an unbalanced force and it will move the way that the greater force is pushing it. if you use only 300 n it will be a balanced force and will not move because the force you are exerting on the   box is the same as its force.

hope this !

im sorry if i went too in depth, i am going to include a link to a video on khan academy that will explain this.   hope that you like the video and that it explains more in detail to you.

that is the link.

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