A. a beam of light is incident from air on the surface of a liquid. if the angle of incidence is 26.7° and the angle of refraction is 18.3°, find the critical angle for the liquid when surrounded by air? b. a light ray, traveling in air, strikes the surface of abeaker of mineral oil at an angle of 37.5° with thenormal to the surface. the speed of light in mineral oil is 2.17 x10^8 m/s.. calculate the angle of refraction.

(a). The critical angle for the liquid when surrounded by air is 44.37°

(b). The angle of refraction is 26.17°.

Explanation:

Given that,

Incidence angle = 26.7°

Refraction angle = 18.3°

(a). We need to calculate the refraction of liquid

Using Snell's law

Put the value into the formula

We need to critical angle for the liquid when surrounded by air

Using formula of critical angle

Put the value into the formula

(b). Given that,

Incidence angle = 37.5°

Speed of light in mineral

We need to calculate the index of refraction

Using formula of index of refraction

Put the value into the formula

We need to calculate the angle of refraction

Using Snell's law

Put the value into the formula

Hence, (a). The critical angle for the liquid when surrounded by air is 44.37°

(b). The angle of refraction is 26.17°.