Two parallel square metal plates that are 1.5 cm and 22 cm on each side carry equal but opposite charges uniformly spread out over their facing surfaces. how many excess electrons are on the negative surface if the electric field between the plates has a magnitude of 18,000 n/c? (k = 1/4 pi epsilon_0 = 9.0 times 10^9 n m^2/c^2, e = 1.6 times 10^-19 c)

The number of excess electrons are on the negative surface is

Explanation:

Given that,

Distance =1.5 cm

Side = 22 cm

Electric field = 18000 N/C

We need to calculate the capacitance in the metal plates

Using formula of capacitance

Put the value into the formula

We need to calculate the potential

Using formula of potential

Put the value into the formula

We need to calculate the charge

Using formula of charge

Put the value into the formula

Here, the charge on both the positive and negative  plates

We need to calculate the number of excess electrons are on the negative surface

Using formula of number of electrons

Put the value into the formula

Hence, The number of excess electrons are on the negative surface is