Avertical spring with spring stiffness constant 305 n/m oscillates with an amplitude of 28.0 cm when 0.235 kg hangs from it. the mass passes through the equilibrium point (y=0) with positive velocity at t=0. positive direction of y-axis is downward.

part a

what equation describes this motion as a function of time?

part b

at what time will the spring stretch to its maximum length at first time?

part c

at what time will the spring shrink to its minimum length at first time?

0.0436 s

0.1308 s

Explanation:

A = Amplitude = 28 cm

m = Mass = 0.235 kg

k = Spring constant = 305 N/m

The equation which describes motion as a function of time is given by

Angular speed is given by

The equation is

Maximum length will be at amplitude

Amplitude is given by

here

The time to stretch to maximum length is 0.0436 s

At minimum length

The time will the spring shrink to its minimum length at first time is 0.1308 s

the results is a decrease in air temperature with an increase of altitude.

explanation: