Two stars m1 and m2 of equal mass make up a binary star system. they move in a circular orbit that has its center at the midpoint of the line that separates them. if m1-m2-6.95 sm (solar mass), and the orbital period of each star is 2.20 days, find their orbital speed. (the mass of the sun is 1.99x 1030 kg.) km/s m2

V = 365643.04 m/s

Explanation:

mass of the sun = 1.99 x 10^{30} kg

mass of M1 = mass of M2 = 6.95 solar mass = 6.95 x 1.99 x 10^{30} = 13.8305x 10^{30} kg  

orbital period of each star (T) = 2.20 days = 2.20 x 24 x 60 x 60 =190,080 s

gravitational constant (G) = 6.67 x 10^{-11} N m2/kg2

orbital speed (V) =

we need to find the orbital radius (r) before we can apply the formula above and we can get it from Kepler's third law, x k

where

making r the subject of the formula we now have

   (take note that π is shown as )

r = 1.38 x 10^{10} m

Now that we have the orbital radius (r) we can substitute all required values into the formula for orbital speed

orbital speed (V) =

V = 365643.04 m/s

the journeys of marquette, joliet and la salle a) new france expand.

all three of these explorers explored the midwest and the area around the great lakes, which they subsequently claimed for france.

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