An electron and a proton are each placed at rest in a uniform electric field of magnitude 560 n/c. calculate the speed of each particle 46.0 ns after being released. electron 4.5e^-6 incorrect.

The speed of electron is and the speed of proton is 2468.02 m/s.

Explanation:

Given that,

Electric field, E = 560 N/C

To find,

The speed of each particle  (electrons and proton) 46.0 ns after being released.

Solution,

For electron,

The electric force is given by :

Let v is the speed of electron. It can be calculated using first equation of motion as :

u = 0 (at rest)

For proton,

The electric force is given by :

Let v is the speed of electron. It can be calculated using first equation of motion as :

u = 0 (at rest)

So, the speed of electron is and the speed of proton is 2468.02 m/s. Therefore, this is the required solution.

air exerts forces on falling objects near earth’s surface.

explanation:

the term 'free falls' refer to object that are falling towards the earth, in a situation in which gravity is the only force acting on the object.

for an object in free fall, the acceleration is constant (g, the gravitational acceleration), and so the velocity of the object constantly increases.

for objects near earth's surface, there is always another force acting on the object: the resistance due to the air. this force is opposed to the direction of fall of the object, and it is proportional to the velocity of the object, so as the object falls down, this force increases up to a point when it balances the force of gravity, and the object continues its motion at constant velocity (called terminal velocity). since in this case gravity is not the only force acting on the object, we are not in a situation of free fall.

force tends to be low and long diustance masses are high