Atoy rocket, mass 0.8 kg, blasts up at a 45 degrees from ground level with a kinetic energy of 41 j. to what maximum vertical height does it rise?

The maximum height reached by the toy rocket is 0.73 meters.

Explanation:

It is given that,

Mass of the toy rocket, m = 0.8 kg

It is projected at an angle of 45 degrees from ground level. The kinetic energy of the rocket is used to find the velocity with which it was projected as :

u = 10.12 m/s

When it reaches to a maximum height, its final velocity will be equal to 0, v = 0

Using third equation of motion to find it as :

a = -g

s is the maximum height reached by the toy rocket

In vertical direction,

s = 0.36 meters

So, the maximum height reached by the toy rocket is 0.73 meters. Hence, this is the required solution.                                          

1.195000

explanation:

total mass=0.0117+0.0137+0.0881+0.0111

total mass= 0.01172kg

total velocity = 0.283-0.743+0.871-0.799+0.155+0.637+0.301=0.102

momentum=mv=0.1172*0.102=1.195000//