The orbital period of a satellite is 2 × 106 s and its total radius is 2.5 × 1012 m. the tangential speed of the satellite is m/s. (round to the nearest whole number, do not add any punctuation.)

The tangential speed of the satellite is 7853982 m/s

Explanation:

To find the tangential speed of the satellite we need the circumference of the orbit.

The circumference is , when the radius of the orbit is . For the case of our satellite,

Now the tangential speed is easy to calculate because it is just the circumference divided by period:

we put in the numbers and get:

d₁ = displacement of tern from arctic to antarctic = 11000 miles

d₂ = displacement of tern from antarctic to arctic =   - 11000 miles

d = total displacement for the journey

total displacement for the journey is given as

d = d₁ + d₂

d = 11000 + (-11000)

d = 0 miles

t₁ = time of travel from arctic to antarctic = 3 months = 3 x 30 days = 90 days

t₂ = time of travel from antarctic to arctic = 3 months = 3 x 30 days = 90 days

t = total time of travel

total time of travel is given as

t = t₁ + t₂

t = 90 + 90

t = 180 days

average velocity is given as

average velocity = total displacement/ total time

v = d/t

v = 0/180

v = 0 miles/day

connect the batteries in series and hope