Two steel plates are to be held together by means of 16-mm-diameter high-strength steel bolts fitting snugly inside cylindrical brass spacers. knowing that the average normal stress must not exceed 216 mpa in the bolts and 143 mpa in the spacers, determine the outer diameter of the spacers that yields the most economical and safe design. the outer diameter of the spacers that yields the most economical and safe design is 34.854 mm

So then the outer diameter for the spaces should be 25.35 in order to have the most economical and safe design.

Explanation:

Let's define some notation first:

represent the tensile stress for the bolt

represent the tensile stress for the spacer

the bolt diameter

the value that we want to find.

For this case we need to remember the definition of tensile stress given by:

And if we solve for P we got:

where P represent the normal stress

For this case we want that the most economical space and we can do this setting equal the both values of P for this case like this:

And if we replace we got:

And if we cancel the constant terms we got:

And if we solve for the variable of interest we got:

And taking common factor we got:

And if we take the square root on both sides we got:

And if we replace we got:

So then the outer diameter for the spaces should be 25.35 in order to have the most economical and safe design.

s the environmental science is a broader field that incorporates many elements of earth and life sciences, whereas ecology is usually more focused on how organisms interact with each other and their surroundings, and often on a very specific population of living things. soo yea

explanation:

  the grams     of oxygen gas   that can be produced     is 20.6   grams of o₂

calculation

2liclo₃ →   2 licl + 3 o₂

step 1:   find the moles of liclo₃

moles = mass÷ molar mass

from periodic table the molar mass of liclo₃ =6.9 +35.5   +(16 x3) =90.4 g/mol

moles=38.7 g÷90.4 g/mol=0.4281   moles

step 2:   use the   mole ratio   to calculate the moles of o2

from equation above, liclo₃: o₂   is 2: 3  

therefore the moles of   o₂=0.4281 moles x3/2 =0.6422   moles

step 3: find mass   of o₂

mass= moles x molar mass

from periodic table the   molar mass of   o₂ = 16 x2= 32 g/mol

mass=0.6422   moles   x   32 g/mol = 20.6 grams of o₂