An object on a vertical spring oscillates up and down in simple harmonic motion with an angular frequency of 14.2 rad/s. calculate the distance d by which the spring stretches from its unstrained length when the object is allowed to hang stationary from it.

0.04865 m

Explanation:

k = Spring Constant

m = Mass

d = Distance

g = Acceleration due to gravity = 9.81 m/s²

Angular frequency is given by

At equilibrium we have

The distance by which the spring stretches from its unstrained length is 0.04865 m

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