Ablock of mass 3.3 kg, sliding on a horizontal
plane, is released with a velocity of 1.8 m/s.
the blocks slides and stops at a distance of
1.5 m beyond the point where it was released.
how far would the block have slid if its
initial velocity were quadrupled?

24 m

Explanation:

initial velocity is u = 3.5 m/sec

final velocity is v = 0 m/sec

distance traveled is S = 1.5 m

From kinematic equation

Making acceleration the subject,

Acceleration

When the initial velocity is quadrupled= u = 3.5*4 = 14 m/s

V = 0 m/s

then

temp rises, and expansion

the order for strong to weak forces such as

strong nuclear force → electromegnetic force → weak nuclear force → gravitational force

the fundamental forces are those forces that act between to objects or element to make interactions. there are four types of fundamental forces such as strong and weak nuclear forces (due to protons and electrons), electromagnetic force (due to the motion of electrons) and gravitational force (due to orbital movement of the planet). if these forces are arranged on the basis of their maximum strength then the order is

strong nuclear force → electromegnetic force → weak nuclear force → gravitational force