Ablock of mass 3.3 kg, sliding on a horizontal
plane, is released with a velocity of 1.8 m/s.
the blocks slides and stops at a distance of
1.5 m beyond the point where it was released.
how far would the block have slid if its
initial velocity were quadrupled?

24 m

Explanation:

initial velocity is u = 3.5 m/sec

final velocity is v = 0 m/sec

distance traveled is S = 1.5 m

From kinematic equation

Making acceleration the subject,

Acceleration

When the initial velocity is quadrupled= u = 3.5*4 = 14 m/s

V = 0 m/s

then

you get 2.3=1.21*\frac{a}2 or 4.6=1.21a or a=3.802 (b)

explanation:

both the fifth and fourteenth amendments of the united states contain a due process clause. while the fifth amendment describes a legal obligation of the federal government to not deprived of life, liberty or property without due process of law, the fourteenth amendment applies the same obligation to the states to guarantee that all of the states provide fair procedures as well.