The strength of the electric field at a certain distance from a point charge is represented by e. what is the strength of the electric field at twice the distance from the point charge?
a) at twice the distance, the strength of the field is e/2.b) at twice the distance, the strength of the field is 2e. c) at twice the distance, the strength of the field is 4e. d) at twice the distance, the strength of the field remains equal to e. e) at twice the distance, the strength of the field is e/4.

E

Explanation:

Using Coulomb's law equation

Force of the charge = k qQ /d²

and E = F/ q

substitute for F

E = ( K Qq/ d² ) / q

q cancel q

E = KQ / d²

so twice  the distance of the from the point charge will lead to the E ( electric field ) decrease by a 4 = E/4. E is inversely proportional to d²

d is the correct answer

hello, i am papaguy.

i have found an answer to your question but use it as information.

information: because weak acids/bases have low concentration of hydrogen ions, the addition of water has a large impact on the ph. 2. a difference in 1 unit is a 10x difference in concentration for example; a liquid with ph of 3 is 10x more acidic than a liquid with a ph of 4. therefore, a liquid with a ph of 3 is stronger.

best of luck!