A)a concentration c(mol/l) varies with time (min) according to the equation c=3.00exp(−2.00t) a) what are the implicit units of 3.00 and 2.00? b) suppose the concentration is measured at t = 0 and t = 1 min. use two-point linear interpolation or extrapolation to estimate c(t=0.6min) and t(c=0.10mol/l) from the measured values, and compare these results with the true values of these quantities. c) sketch a curve of c versus t, and show graphically the points you determined in part (b).

a. 3.00 must be in mol/L and 2.00 in 1/min.

b. Using lineal equation:

t = 0.6 min then C = 1.45 mol/L

C = 0.10 mol/L then t = 1.12 min

Using exponential equation:

t = 0.6 min then C = 0.90 mol/L

C = 0.10 mol/L then t = 1.70 min

Explanation:

a) C is in mol/L so, as we know that the exponential does not have units, 3.00 must be in mol/L and 2.00 in 1/min.

b) If we want to make a line between 0 an 1 we need to find the linear equation for this.

We can use the slope intercept-equation:

y = ax + b (1)

Let's find a and b.

a is the slope of here, so we can use the next equation to find it:

We have two points, (0,C₁) and (1,C₂)

So a will be:

We can use the equation (1) to find b, for instance, let's choose:

Finally, our linear equation will be: or  

Using lineal equation:

t = 0.6 min then C = 1.45 mol/L

C = 0.10 mol/L then t = 1.12 min

Using exponential equation:

t = 0.6 min then C = 0.90 mol/L

C = 0.10 mol/L then t = 1.70 min

I hope it helps you!

in simple terms, the principle states that the buoyancy force on an object is equal to the weight of the fluid displaced by the object, or the density of the fluid multiplied by the submerged volume times the gravitational acceleration, g. this is also known as upthrust.

0.19 m/s and 0.45 m/s