If a ball dropped from a tower reaches the ground after 3.5 seconds, what is the height of the tower? given: g = -9.8 meters/second2

To find the height of the tower, a formula for free-fall motion can be used, especially since the time and the force of gravity are given. The formula is shown below:

h = (1/2)*g*t^2

Where:

h = height of the tower = ?
g = acceleration due to gravity = -9.8 m/s^2
t = time = 3.5 seconds

Substituting the given values:

h = (1/2)*(9.8)*(3.5)^2
h = 60.025 meters

Hypothesis. why don’t you know this? i learned this stuff in like 5th grade