Aweight of 12.0 n hangs motionless from a spring, with a spring constant of 10.0 n/m. how far is the spring stretched from its original length?

0.120 m
0.220 m
0.833 m
1.20 m

0.120 m

Explanation:

F=kx where F is force and k is constant, x is extension from its original length

Making x the subject then substituting 12 N for F and 10.0 N/m for k then

1.2m

Explanation:

According to hookes law which States that the extension of an elastic material is directly proportional to the applied force provided that the elastic limit is not exceeded. Mathematically, F = ke where;

F is the applied force = 12.0N

k is the elastic constant = 10N/m

e is the extension = ?

Substituting the values into the formula to get the extension, we have e = F/k

e ,= 12N/10N/m

e = 1.2m

This shows that the string have been stretched by 1.2m from its original length

convex lenses are thicker at the middle. rays of light that pass through the lens are brought closer together (they converge). a convex lens is a converging lens. when parallel rays of light pass through a convex lens the refracted rays converge at one point called the principal focus.

a) electrical > light, sound, and thermal< < < <

) the mechanical energy of the firefighter moving.< < < < a) electrical > light, sound, and thermal< < < <

c) both a and b.