Asatellite orbiting the earth is directly over a point on the equator at 12: 00 midnight every three days. it is not over that point at any time in between.
what is the radius of the satellite's orbit?

the radius of the satellite's orbit  is  r = 8.78×10⁷m

Explanation:

given the time period, T= 3days

converting the time in days to seconds is given as;

time, T=(3*24*60*60) sec

T=259200 sec

from the force relation;

mv²/r = Gm×M/r²

v²=G×M/r (1)

and

V=2pi×r/T

V²=4×pi²×r²/T²

>

from equation  (1) , we have

4×pi²×r²/T²=G×M/r

this becomes;  4×pi²×r³/T² = G×M

r³ = G×M×T²/(4pi²)

r³ = 6.67×10⁻¹¹×(5.97×10²⁴)×(259200)²/(4pi²)

==> r=8.78×10⁷m

radius of the orbit, r=8.78×10⁷ m

distance = 150m

displ = root (50 ^2 + 100^2)

root(2500+10000)

root 125000