Carbon-14 has a half-life of 5,700 years. how long will it take for 6.25% of the carbon-14 to be remaining?

22,800 years

Explanation:

Half life equation:

A = A₀ (½)^(t / T)

where A is the final amount,

A₀ is the initial amount,

t is time,

and T is the half life.

0.0625 = (½)^(t / 5700)

log 0.0625 = (t / 5700) log 0.5

4 = t / 5700

t = 22,800

It takes 22,800 years.

a 2,000 calorie based diet.