Arectangular tank contains water to a dept of 2m. if the base is 4m × 3m, calculate the force on the base (density of water = 10³kgm³ g = 10m/s/s)

16.7 N

Explanation:

First, we need to find the Pressure at the base of the water. The pressure in liquids be calculated by the formula:

P = dgh where

d is the density of liquid in kg/m^3

g is the gravitational field strength in m/s^2

h is the height of liquid column

With this formula, we can see that:

Pressure at base = (10)(10)(2)

= 200 Pa

We also know that Pressure is the amount of Force acting per unit area of object with the formula:

P = F/A where

F is the amount of Force in N

A is the area of the body in m^2

Hence by applying the formula, we get:

200 = F(4×3)

12F = 200

F = 16.7 N

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unbalanced force

explanation: