Agolfer is on the edge of a 12.5 m bluff overlooking the 18th hole which is located 60 m from the base of the bluff. she launches a horizontal shot that lands in the hole on the fly. the gallery erupts in cheers.

The ball impact velocity i.e(velocity right before landing) is 6.359 m/s

Explanation:

This problem is related to parabolic motion and can be solved by the following equations:

----------------------(1)

---------(2)

----------------------- (3)

Where:

x = m is the horizontal distance travelled by the golf ball

is the golf ball's initial velocity

is the angle (it was  a horizontal shot)

t is the time

y is the final height of the ball

is the initial height of the ball

g is the acceleration due gravity

V is the final velocity of the ball

Step 1: finding t

Let use the equation(2)

s

Substituting (6) in (1):

-------------------(4)

Step 2:  Finding :

From equation(4)

m/s (8)  

Substituting in (3):

v =42 .01 - 15.3566  

V=26.359 m/s

6 cos 34, 6 sin 34 trig