Arocket moves straight upward , starting from rest with an acceleration of 29.4 m/s2. it runs out of fuel at the end of 4.00 s and countinues to coast upward , reaching a maximum height before falling back to earth .

a) find the rocket's velocity and position at the end of 4.00 s .
b) find the maximum height the rocket reaches.
c) find the velocity the instant before the rocket crashes on the ground

117.6 m/s, 235.2 m

940.08073 m

135.81 m/s

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

g = Acceleration due to gravity = 9.81 m/s² = a

The velocity at the end of 4 seconds is 117.6 m/s

Position at the end of 4 seconds is 235.2 m above the ground

Maximum height of the rocket is 704.88073+235.2 = 940.08073 m

Velocity of the rocket as it crashes is 135.81 m/s

i think the answer is b

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explanation: