A62.4 kg ice skater moving to the right with a velocity of 2.67 m/s throws a 0.198 kg snow ball to the right with a velocity of 39.7 m/s relative to the ground. t is the velocity of the ice skater after throwing the snowball? disregard the friction between the skates and the ice. answer in units of m/s

a second skater initially at rest with a mass of 58.4 kg catches the snowball. what is the velocity of the second skater after catching the snowball in a perfectly inelastic collision? answer in units of m/s

The final velocity of the first skater is 2.544 m/s and the velocity of the second skater is 0.134 m/s.

In this question, the concepts of conservation of momentum and perfectly inelastic collision are to be used.

let, m(1) = 62.4 kg , m(b) = 0.198 kg and m(2) = 58.4 kg be the masses of the first skater, the ball and the second skater respectively.

(i) the first skater throws the ball

Their initial velocities are u(1) = 2.67 m/s , u(b) =0

and the final velocities are v(1) , v(b) = 39.7 m/s

Applying conservation off momentum:

   m(1)u(1) + m(b)u(b) = m(1)v(1) + m(b)v(b)

62.4 × 2.67 + 0.198 × 0 = 62.4 × v(1) + 0.198 × 39.7

v(1) =

v(1) = 2.544 m/s is the final speed of the first skater after throwing th ball.

(ii) The second skater catches the ball

Here the collision is perfectly inelastic, both the ball and skater move with the same velocity (v) after catching the ball.

Applying conservation of momentum

m(b)v(b) = [m(2) + m(b)] v

0.198 × 39.7 = [58.4 + 0.198] v

v = 0.134 m/s is the velocity of the second skater after catching the ball.

Learn more about elastic and inelastic collision:

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0.11 m/s and 0.28 m/s should be correct